z^2-14z+42=0

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Solution for z^2-14z+42=0 equation:


Simplifying
z2 + -14z + 42 = 0

Reorder the terms:
42 + -14z + z2 = 0

Solving
42 + -14z + z2 = 0

Solving for variable 'z'.

Begin completing the square.

Move the constant term to the right:

Add '-42' to each side of the equation.
42 + -14z + -42 + z2 = 0 + -42

Reorder the terms:
42 + -42 + -14z + z2 = 0 + -42

Combine like terms: 42 + -42 = 0
0 + -14z + z2 = 0 + -42
-14z + z2 = 0 + -42

Combine like terms: 0 + -42 = -42
-14z + z2 = -42

The z term is -14z.  Take half its coefficient (-7).
Square it (49) and add it to both sides.

Add '49' to each side of the equation.
-14z + 49 + z2 = -42 + 49

Reorder the terms:
49 + -14z + z2 = -42 + 49

Combine like terms: -42 + 49 = 7
49 + -14z + z2 = 7

Factor a perfect square on the left side:
(z + -7)(z + -7) = 7

Calculate the square root of the right side: 2.645751311

Break this problem into two subproblems by setting 
(z + -7) equal to 2.645751311 and -2.645751311.

Subproblem 1

z + -7 = 2.645751311 Simplifying z + -7 = 2.645751311 Reorder the terms: -7 + z = 2.645751311 Solving -7 + z = 2.645751311 Solving for variable 'z'. Move all terms containing z to the left, all other terms to the right. Add '7' to each side of the equation. -7 + 7 + z = 2.645751311 + 7 Combine like terms: -7 + 7 = 0 0 + z = 2.645751311 + 7 z = 2.645751311 + 7 Combine like terms: 2.645751311 + 7 = 9.645751311 z = 9.645751311 Simplifying z = 9.645751311

Subproblem 2

z + -7 = -2.645751311 Simplifying z + -7 = -2.645751311 Reorder the terms: -7 + z = -2.645751311 Solving -7 + z = -2.645751311 Solving for variable 'z'. Move all terms containing z to the left, all other terms to the right. Add '7' to each side of the equation. -7 + 7 + z = -2.645751311 + 7 Combine like terms: -7 + 7 = 0 0 + z = -2.645751311 + 7 z = -2.645751311 + 7 Combine like terms: -2.645751311 + 7 = 4.354248689 z = 4.354248689 Simplifying z = 4.354248689

Solution

The solution to the problem is based on the solutions from the subproblems. z = {9.645751311, 4.354248689}

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